6y^2-57y+135=0

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Solution for 6y^2-57y+135=0 equation:



6y^2-57y+135=0
a = 6; b = -57; c = +135;
Δ = b2-4ac
Δ = -572-4·6·135
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-3}{2*6}=\frac{54}{12} =4+1/2 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+3}{2*6}=\frac{60}{12} =5 $

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